A magnet exerts a force of 4 N on a steel ball at a distance of 0.3 meters, and a force of 16 N at a distance of 0.15 meters (an inverse square relationship). If the steel ball is released from a position 1 meter above the same magnet, what will be the steel ball’s kinetic energy when it is 0.01 m away from the magnet? (neglect all outside forces)
Chosen Answer:
way to the solution:
Kinetic energy of the ball = (work of gravitation)+(work of magnetic field) = integrate(gravit. force+magnetic force)*dx (from x= 1m to x=0.01 m)
by: r_vike
on: 19th December 06
